C PROGRAMMING-- ARMSRONG NO.

#include<stdio.h>
#include<conio.h>
void main()
{ clrscr();
int n,r,x,s=0,n1;
printf("ENTER THE NO.=\n");
scanf("\n%d",&n);
n1=n;
while(n>0)
{ r=n%10;
n=n/10;
x=r*r*r;
s=s+x;
}
if(n1==s)
{  printf("ARMSTRONG NO.!!!\n");
}
else
{
printf("not a armstrong no.=\n");
}
getch();
}